Ответ:
25 435
CaCO3 + 2 HCl → CaCl2 + H2O + CO2
3.6 1.8
m(HCl) = 435 * 0.3 = 130.5 г
n(HCl) = 130.5/36.5 = 3.6 моль
n(CO2) = n(HCl)/2 = 1.8 моль
V(CO2) = 1.8 * 22.4 = 40.32 л
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Ответ:
25 435
CaCO3 + 2 HCl → CaCl2 + H2O + CO2
3.6 1.8
m(HCl) = 435 * 0.3 = 130.5 г
n(HCl) = 130.5/36.5 = 3.6 моль
n(CO2) = n(HCl)/2 = 1.8 моль
V(CO2) = 1.8 * 22.4 = 40.32 л