Ответ:

[tex]x=5[/tex]

Объяснение:

[tex]\frac{2}{x+5} +\frac{3}{2x-10} = \frac{15}{x^{2} -25}[/tex]

[tex]\frac{2}{x+5} +\frac{3}{2x-10} -\frac{15}{x^{2} -25}=0[/tex]

[tex]\frac{2}{x+5} +\frac{3}{2(x-5)} - \frac{15}{(x-5)(x+5)}=0[/tex]      |[tex]*2(x-5)(x+5)[/tex]

[tex]2*2(x-5) + 3(x+5) -15*2 = 0\\4x-20+3x+15-30 = 0\\7x = 35\\x = 5[/tex]