Verified answer

[tex]\displaystyle (2|x|-\frac{2}{3})(4-\frac{x}{6})=0\\ \\2|x|-\frac{2}3}=0;4-\frac{x}{6}=0\\ \\x_1=-\frac{1}{3},x_2=\frac{1}{3},x_3=24[/tex]

объяснение:

[tex]\displaystyle 1)2|x|-\frac{2}{3}=0\\ \\2|x|=\frac{2}{3}\\ \\|x|=\frac{1}{3}\\ \\x=б\frac{1}{3}\\\\2)4-\frac{x}{6}=0\\ \\x=24[/tex]