[tex]\displaystyle (6\frac{1}{4}*2\frac{2}{15}-5\frac{1}{3}:\frac{8}{9}):11+1\frac{3}{4}-\frac{3}{4}=(\frac{25}{4}*\frac{32}{15}-\frac{16}{3}*\frac{9}{8})*\frac{1}{11}+\frac{7}{4}-\frac{3}{4}=\\\\(5*\frac{8}{3}-2*3)*\frac{1}{11}+\frac{7}{4}-\frac{3}{4}=(\frac{40}{3}-6)*\frac{1}{11}+\frac{7}{4}-\frac{3}{4}=\frac{22}{3}*\frac{1}{11}+\frac{7}{4}-\frac{3}{4}=\\\\\frac{2}{3}+\frac{7}{4}-\frac{3}{4}=\frac{5}{3}=1\frac{2}{3}[/tex]