Ответ:
Объяснение:
1) [tex]x^{n+1}(x^{n+6}-1)-x^{n+2}(x^{n+5}-x^3)= x^{n+1+n+6}-x^{n+1}-x^{n+2+n+5}+x^{n+2+3}=\\=x^{2n+7}-x^{n+1}-x^{2n+7}+x^{n+5}=x^{n+5}-x^{n+1}=x^{n+1}(x^4-1)[/tex]
2) [tex]x^{n+2}(x^2-3)-x^n(x^{n+2}-3x^2-1)=x^{n+2+2}-3x^{n+2}-x^{n+n+2}+3x^{n+2}+x^n=\\=x^{n+4}-x^{2n+2}+x^n[/tex]
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Ответ:
Объяснение:
1) [tex]x^{n+1}(x^{n+6}-1)-x^{n+2}(x^{n+5}-x^3)= x^{n+1+n+6}-x^{n+1}-x^{n+2+n+5}+x^{n+2+3}=\\=x^{2n+7}-x^{n+1}-x^{2n+7}+x^{n+5}=x^{n+5}-x^{n+1}=x^{n+1}(x^4-1)[/tex]
2) [tex]x^{n+2}(x^2-3)-x^n(x^{n+2}-3x^2-1)=x^{n+2+2}-3x^{n+2}-x^{n+n+2}+3x^{n+2}+x^n=\\=x^{n+4}-x^{2n+2}+x^n[/tex]