[tex](2 - \sqrt{3} )( \sqrt{3} + 1) = 2 \sqrt{3} + 2 - \sqrt{3} \times \sqrt{3} - \sqrt{3 } = \sqrt{3} + 2 - 3 = \sqrt{3} - 1 [/tex]
[tex]( \sqrt{2} + \sqrt{5} )(2 \sqrt{2} - \sqrt{5} ) = 2 \sqrt{2} \times \sqrt{2} - \sqrt{2 } \times \sqrt{5} + 2 \sqrt{2} \times \sqrt{5} - \sqrt{5} \times \sqrt{5} = 4 - \sqrt{10} + 2 \sqrt{10} - 5 = \sqrt{10} - 1[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
[tex](2 - \sqrt{3} )( \sqrt{3} + 1) = 2 \sqrt{3} + 2 - \sqrt{3} \times \sqrt{3} - \sqrt{3 } = \sqrt{3} + 2 - 3 = \sqrt{3} - 1 [/tex]
[tex]( \sqrt{2} + \sqrt{5} )(2 \sqrt{2} - \sqrt{5} ) = 2 \sqrt{2} \times \sqrt{2} - \sqrt{2 } \times \sqrt{5} + 2 \sqrt{2} \times \sqrt{5} - \sqrt{5} \times \sqrt{5} = 4 - \sqrt{10} + 2 \sqrt{10} - 5 = \sqrt{10} - 1[/tex]