Ответ:
1)A
2)A
3)Б
4)Г
5)Б
6)
1.B
2.Д
3.Г
4.Б
Объяснение:
4)
[tex] \frac{6}{ \sqrt{3} } = \frac{6}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } = \frac{6 \sqrt{3} }{3} = 2 \sqrt{3} [/tex]
1.
[tex] \sqrt{ \frac{9}{4} } + \sqrt{3 + \sqrt{36} } = \frac{3}{2} + \sqrt{3 + 6} = 1.5 + \sqrt{9} = 1.5 + 3 = 4.5[/tex]
2.
[tex] \sqrt{45 \times 10} = \sqrt{9 \times 5 \times 2 \times 5} = 3 \times 5 \sqrt{2} = 15 \sqrt{2} [/tex]
3.
[tex] \sqrt{10} - \sqrt{40} = \sqrt{10} - \sqrt{4 \times 10} = \sqrt{10} - 2 \sqrt{10} = - \sqrt{10} [/tex]
4.
[tex] \sqrt{300} - \sqrt{75} = \sqrt{100 \times 3} - \sqrt{25 \times 3} = 10 \sqrt{3} - 5 \sqrt{3} = 5 \sqrt{3} [/tex]
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Answers & Comments
Ответ:
1)A
2)A
3)Б
4)Г
5)Б
6)
1.B
2.Д
3.Г
4.Б
Объяснение:
4)
[tex] \frac{6}{ \sqrt{3} } = \frac{6}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } = \frac{6 \sqrt{3} }{3} = 2 \sqrt{3} [/tex]
6)
1.
[tex] \sqrt{ \frac{9}{4} } + \sqrt{3 + \sqrt{36} } = \frac{3}{2} + \sqrt{3 + 6} = 1.5 + \sqrt{9} = 1.5 + 3 = 4.5[/tex]
2.
[tex] \sqrt{45 \times 10} = \sqrt{9 \times 5 \times 2 \times 5} = 3 \times 5 \sqrt{2} = 15 \sqrt{2} [/tex]
3.
[tex] \sqrt{10} - \sqrt{40} = \sqrt{10} - \sqrt{4 \times 10} = \sqrt{10} - 2 \sqrt{10} = - \sqrt{10} [/tex]
4.
[tex] \sqrt{300} - \sqrt{75} = \sqrt{100 \times 3} - \sqrt{25 \times 3} = 10 \sqrt{3} - 5 \sqrt{3} = 5 \sqrt{3} [/tex]