Объяснение:
[tex]\displaystyle\\3x^2-2x-8=3x^2-6x+4x-8=3x*(x-2)+4*(x-2)=(x-2)*(3x+4).\\\\x_1=2\ \ \ \ \ \ x_2=-\frac{4}{3}.[/tex]
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Объяснение:
[tex]\displaystyle\\3x^2-2x-8=3x^2-6x+4x-8=3x*(x-2)+4*(x-2)=(x-2)*(3x+4).\\\\x_1=2\ \ \ \ \ \ x_2=-\frac{4}{3}.[/tex]