Ответ:

х≠ -3

[tex] {x}^{2} - x - 2 = 0 \\ {x}^{2} + x - 2x - 2 = 0 \\ x(x + 1) - 2(x + 1) = 0 \\ (x + 1)(x - 2) = 0 \\ x + 1 = 0 \\ x - 2 = 0[/tex]

х= -1

х=2