Ответ:
[tex] - \frac{3}{10} y[/tex]
[tex]\displaystyle\bf\\\frac{3}{7}\Big(0,56x-4,9y\Big)-\frac{6}{13}\Big(0,52x-3,9y\Big) =\\\\\\=\frac{3}{7}\cdot 0,56x-\frac{3}{7}\cdot 4,9y-\frac{6}{13}\cdot0,52x+\frac{6}{13} \cdot3,9y =\\\\\\=3\cdot 0,08x-3\cdot0,7y-6\cdot0,04x+6\cdot0,3y=\\\\\\=0,24x-2,1y-0,24x+1,8y=-0,3y[/tex]
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Ответ:
[tex] - \frac{3}{10} y[/tex]
[tex]\displaystyle\bf\\\frac{3}{7}\Big(0,56x-4,9y\Big)-\frac{6}{13}\Big(0,52x-3,9y\Big) =\\\\\\=\frac{3}{7}\cdot 0,56x-\frac{3}{7}\cdot 4,9y-\frac{6}{13}\cdot0,52x+\frac{6}{13} \cdot3,9y =\\\\\\=3\cdot 0,08x-3\cdot0,7y-6\cdot0,04x+6\cdot0,3y=\\\\\\=0,24x-2,1y-0,24x+1,8y=-0,3y[/tex]