Ответ:
дано
mтеор (Mg2Si) = 15.2 g
η(Mg2Si) = 89%
----------------------
V(SiH4)-?
Mg2Si+4H2O-->SiH4+2Mg(OH)2
m пр(Mg2Si) = 15.2 * 89%/100% = 13.528 g
M(Mg2Si) = 76 g/mol
n(Mg2Si) = m/M = 13.528 / 76 = 0.178 mol
n(Mg2Si) = n(SiH4) = 0.178 mol
V(SiH4) = n*Vm = 0.178 * 22.4 = 3.987 L
ответ 3.987 л
Объяснение:
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Ответ:
дано
mтеор (Mg2Si) = 15.2 g
η(Mg2Si) = 89%
----------------------
V(SiH4)-?
Mg2Si+4H2O-->SiH4+2Mg(OH)2
m пр(Mg2Si) = 15.2 * 89%/100% = 13.528 g
M(Mg2Si) = 76 g/mol
n(Mg2Si) = m/M = 13.528 / 76 = 0.178 mol
n(Mg2Si) = n(SiH4) = 0.178 mol
V(SiH4) = n*Vm = 0.178 * 22.4 = 3.987 L
ответ 3.987 л
Объяснение: