30 баллов за решение!!!. Created by Znauka228. algebra-ru

30 баллов за решение!!!...

Znauka228 @Znauka228

July 2022 1 5 Report

30 баллов за решение!!!

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mukus13

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$( \frac{(a-3b)^2}{4(a-6b)} -4a): \frac{3a+18b}{56a-48} * \frac{a^2-36b^2}{5a^2-30ab-3b^2} = \frac{a^2+9b^2-6ab-16a(a-6b)}{4(a-6b)} * \frac{8(7a-6)}{3(a+6b)} *$ $\frac{(a-6b)(a+6b)}{5a^2-30ab-3b^2} = \frac{a^2+9b^2-6ab-16a^2+96ab}{4(a-6b)} * \frac{8(7a-6)}{3(a+6b)} * \frac{(a-6b)(a+6b)}{5a^2-30ab-3b^2}=$ $\frac{-15a^2+9b^2+90ab}{4(a-6b)} * \frac{8(7a-6)}{3(a+6b)} * \frac{(a-6b)(a+6b)}{5a^2-30ab-3b^2}=\frac{-3(5a^2-3b^2-30ab)}{4(a-6b)} * \frac{8(7a-6)}{3(a+6b)} *$ $\frac{(a-6b)(a+6b)}{5a^2-30ab-3b^2}=-2*(7a-6)$

$a= \frac{1}{7}$

$-2*(7a-6)=-2*(7* \frac{1}{7} -6)=-2*(-5)=10$

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