№6
(3-b)(3+b)(9+b2)+(4+b2)2=(9-b2)(9+b2)+16+8b2+b4= 81-b4+16+8b2+b4=
=65+8b2=65+2=67
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№6
(3-b)(3+b)(9+b2)+(4+b2)2=(9-b2)(9+b2)+16+8b2+b4= 81-b4+16+8b2+b4=
=65+8b2=65+2=67