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Rozalina9
@Rozalina9
August 2022
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Найдите ctg(x-y), если cos(x+3y)+cos(3x+y)=1 и sin(x+3y)-sin(3x+y)=1/3
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kuchinaalinka
1) y'=1/(sin^2(1-x))2) y'=-sinx^3*3x^2+6x3) y'=2x*tgx+x^2*1/(cos^2x)4) y'=cos(tgx)*1/(cos^2x)
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