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Ответ:

45П

Объяснение:

Sосн = 9π

[tex]\displaystyle\bf\\\pi R^{2} =9\pi\\\\R^{2}=9\\\\R=\sqrt{9} =3[/tex]

Sсеч = 2RH

[tex]\displaystyle\bf\\2RH=30\\\\H=\frac{30}{2R} =\frac{15}{R} =\frac{15}{3} =5\\\\\\V=\pi R^{2} H=9\pi \cdot 5= 45\pi[/tex]