Ответ на задание в фотографии:
1)
f (х) = 2х + 1/х
f (-1) = 2 * (-1) + 1/(-1) = -2 - 1 = -3
f (1/2) = 2 * 1/2 + 1/(1/2) = 1 + 2 = 3
f (8) = 2 * 8 + 1/8 = 16 + 1/8 = 16 1/8
2)
f( х) = √(10х - х²)
f (0) = √(10* 0 - 0²) = √0 = 0
f (1) = √(10 * 1 - 1²) = √(10 - 1) √9 = ± 3
f (2) = √(10 * 2 - 2²) = √(20 - 4) = √16 = ± 4
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Ответ на задание в фотографии:
1)
f (х) = 2х + 1/х
f (-1) = 2 * (-1) + 1/(-1) = -2 - 1 = -3
f (1/2) = 2 * 1/2 + 1/(1/2) = 1 + 2 = 3
f (8) = 2 * 8 + 1/8 = 16 + 1/8 = 16 1/8
2)
f( х) = √(10х - х²)
f (0) = √(10* 0 - 0²) = √0 = 0
f (1) = √(10 * 1 - 1²) = √(10 - 1) √9 = ± 3
f (2) = √(10 * 2 - 2²) = √(20 - 4) = √16 = ± 4