Даю сто баллов! Срочно! 2х-y/х-3y при х = -1, у =1/3. Created by danuciki. algebra-ru

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$\displaystyle \tt \frac{2x-y}{x-3y}=\frac{2\cdot(-1)-\dfrac{1}{3}}{-1-3\cdot\dfrac{1}{3}}= -2\frac{1}{3}:(-2)=\frac{7}{3}\cdot\frac{1}{2}=\frac{7}{6}=1\frac{1}{6};$

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Regent1828

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Ответ:

Объяснение:

(2x-y)/x-3y) pri x=-1 ,y =1/3

(2*(-1)-1/3)/(-1-3(1/3)) = (-2-1/3)/(-1-1)=-7/3 /-2=7/6=7,1(6)

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