Очень срочно нужно, пожалуйста решите!!! Найти sin^2(45-a)=?, если sin2a= 1/3. Created by Yana4660. algebra-ru

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Yana4660 @Yana4660

July 2022 1 3 Report

Очень срочно нужно, пожалуйста решите!!!
Найти sin^2(45-a)=?, если sin2a= 1/3

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oganesbagoyan

Verified answer

Sin²(45-α) =(1-cos2*(45°-α))/2 =(1-cos(90°-2α))/2=
(1-sin2α)/2=(1-1/3)/2=(2/3)/2 =1/3.

* * * cos2α =cos²α -sin²α =1-sin²α -sin²α =1-2sin²α⇒sin²α=(1-cos2x)/2 * * *

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