Найти производную функции y=(2sinx) ^{-2/3}. Created by mixgirl. algebra-ru

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mixgirl @mixgirl

July 2022 1 21 Report

Найти производную функции y=(2sinx) ^{-2/3}

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Artem112

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$y=(2\sin x) ^{- \frac{2}{3} }=
\\\
y`=((2\sin x) ^{- \frac{2}{3} })`=- \frac{2}{3}(2\sin x) ^{- \frac{2}{3}-1 }\cdot(2\sin x)`=
- \frac{4\cos x}{3}(2\sin x) ^{- \frac{5}{3} }$

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mixgirl June 2022 | 0 Ответы

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