30баллов.докажите тождества:
(7х-3у)-(7х+2у)²+70х=5у
(2а+5)³=(2а+3)³+24а²+96а+98
и третье еще сделать
(7х-3у)-(7х+2у)²+70х=5у
(2а+5)³=(2а+3)³+24а²+96а+98
и третье еще сделать
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Ответ:
№1 (7x-3y)^2-(7x+2y)^2+70x=5y <=> 49x^2-42xy+9y^2-49x^2-28xy-4y^2+70xy= 5y^2 <=> 9y^2-4y^2 = 5y^2 <=> 5y^2=5y^2
№2 (2a+5)^3 = (2a+3)^3 +24a^2+96a+98 <=> (2a+5)^3 = 8a^3 +36a^2+54a+27+24a^2+96a+98 <=> (2a+5)^3 = 8a^3+ 60a^2 + 150a + 125 <=> (2a+5)^3 = (2a+5)^3
№3 (1/3x+6y)*(1/3-6y)+38y^2 = 1/9x^2+2y^2 <=> 1/9x^2-36y^2+38y^2 = 1/9x^2+ 2y^2<=> 1/9x^2+2y^2 = 1/9x^2+2y^2
Объяснение: