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ilushka63
@ilushka63
July 2022
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Решить уравнение:
sin(2x-пи/3)=0
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nafanya2014
Verified answer
Sin(2x-(π/3))=0
2x-(π/3)=πk, k∈Z
2x=(π/3)+πk, k∈Z
x=(π/6)+(π/2)·k, k∈Z
О т в е т. x=(π/6)+(π/2)·k, k∈Z
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Answers & Comments
Verified answer
Sin(2x-(π/3))=02x-(π/3)=πk, k∈Z
2x=(π/3)+πk, k∈Z
x=(π/6)+(π/2)·k, k∈Z
О т в е т. x=(π/6)+(π/2)·k, k∈Z