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Meqaton
@Meqaton
July 2022
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Помогите представить эту дробь!
(6^-3*18^7)/3^10
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Anna456anna
Приводим к одинаковому основанию это 3. => (2*3)^-3 * (2*3*3)^7/3^10 =>
2^-3+7 *3^-3+7+7/3^10 =>
2^4*3^11/3^10 =>
2^4 * 3^11-10 =>
2^4*3^1 =>
16*3 = 48
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Answers & Comments
2^-3+7 *3^-3+7+7/3^10 =>
2^4*3^11/3^10 =>
2^4 * 3^11-10 =>
2^4*3^1 =>
16*3 = 48