НАЙДИТЕ ОБЛАСТЬ ЗНАЧЕНИЯ ФУНКЦИИ, ЗАДАНОЙ ФОРМУЛОЙ
y=1-cos^2*2пиХ/3
-1<=cost<=1-1<=cos(2пиХ/3)<=10<=cos^2(2пиХ/3)<=1-1<=-cos^2(2пиХ/3)<=00<=1-cos^2(2пиХ/3)<=1Ответ: от 0 до 1
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Answers & Comments
-1<=cost<=1
-1<=cos(2пиХ/3)<=1
0<=cos^2(2пиХ/3)<=1
-1<=-cos^2(2пиХ/3)<=0
0<=1-cos^2(2пиХ/3)<=1
Ответ: от 0 до 1