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nataa2
@nataa2
September 2021
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вычислите пожалуйста очень надо
1)tg60° 2cos45°-√3ctg45°
2)6cos 30°-3tg 60°+2sin45°
3)√3tg 30°+4sin30°-√3ctg 30°
4)√3sin Π/3-2cosΠ/6+√3/2tgΠ/3
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pyankova1968
1) =√3*2*√2/2-3*1=√6-3
2) =6*√3/2-3√3+2*√2/2=√2
3) =√3*√3/3+4*1/2-√3*√3=0
4) =√3*√3/2-2*√3/2+√3/2*√3=3-√3
11 votes
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nataa2
спасибо большое
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Answers & Comments
2) =6*√3/2-3√3+2*√2/2=√2
3) =√3*√3/3+4*1/2-√3*√3=0
4) =√3*√3/2-2*√3/2+√3/2*√3=3-√3