8 класс.Тема:Формула корней квадратного уравнения.
а)а^2=5a-4
b)(x-3)^2=(2-x)(x-3)
в)(y+2)(y-2)= -6(y+2)
г)q(q-1)=q+15/3
а)а^2=5a-4
b)(x-3)^2=(2-x)(x-3)
в)(y+2)(y-2)= -6(y+2)
г)q(q-1)=q+15/3
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Answers & Comments
a²-5a+4=0;
(a-1)(a-4)=0;
a₁=1;a₂=4;
b)(x-3)²=(2-x)(x-3);
x-3=0 или x-3=2-x
x₁=3; 2x= -1;
x₂= -0.5;
c)(y+2)(y-2)= -6(y+2)
y+2=0 или y-2= -6
y₁= -2; y₂= -4;
d)q(q-1)=q+15/3;
q²-q=q+5;
q²-2q-5=0;
D=4+4*5=24
q₁= (2+2√6)/2=1+√6; q₂=1-√6;