Верно ли равенство? 1) 9(b+1 2/3)^2-21(2b+1)-(3b-2)^2-200=0 2) 15(5a+6)(6-5a)+13(6a-1)^2-31(17+3a^2)-26=-156a. Created by PlayerTheMineToCraft. algebra-ru

1) 9(b+1 2/3)^2-21(2b+1)-(3b-2)^2-200=0Ответ : Ложь. -200 ≠ 02) 15(5a+6)(6-5a)+13(6a-1)^2-31(17+3a^2)-26=-156aОтвет : Верно.

3)^2-21(2b+1)-(3b-2)^2-200=0 2) 15(5a+6)(6-5a)+13(6a-1)^2-31(17+3a^2)-26=-156a...

PlayerTheMineToCraft @PlayerTheMineToCraft

June 2022 1 7 Report

Верно ли равенство?
1) 9(b+1 2/3)^2-21(2b+1)-(3b-2)^2-200=0

2) 15(5a+6)(6-5a)+13(6a-1)^2-31(17+3a^2)-26=-156a

Answers & Comments

DenisVolk01 1) 9(b+1 2/3)^2-21(2b+1)-(3b-2)^2-200=0

$9b^{2}+30b+25-42b-21-9b^{2}+12b-4-200=0 \\ 9b^{2}-9b^{2}+30b+12b-42b+25-21-4-200=0 \\ 42b-42b+25-25-200=0 \\ -200 \neq 0$

Ответ : Ложь. -200 ≠ 0

2) 15(5a+6)(6-5a)+13(6a-1)^2-31(17+3a^2)-26=-156a
$-15(25a^{2}-36)+13(36a^{2}-12a+1)-31(3a^{2}+17)-26=-156a \\ -375a^{2}+540+468a^{2}-156a+13-93a^{2}-527-26=-156a \\ -375a^{2}+468a^{2}-93a^{2}-156a+540+13-527-26=-156a \\ 468a^{2}-468a^{2}-156a+553-553=-156a \\ -156a=156a$
Ответ : Верно.

3 votes Thanks 3

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