[tex]\displaystyle\bf\\\frac{32^{3}\cdot 8^{2} }{16^{5} }=\frac{(2^{5})^{3}\cdot(2^{3} )^{2} }{(2^{4})^{5} } =\frac{2^{15}\cdot 2^{6} }{2^{20} }=\frac{2^{15+6} }{2^{20} } =\frac{2^{21} }{2^{20} } =2^{21-20} =2^{1} =2[/tex]