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Ответ:

Объяснение:

[tex]1)\frac{10}{x} -3=x\\10-3x=x^{2} \\x^{2} +3x-10=0\\x^{2} -2x+5x-10=0\\x(x-2)+5(x-2)=0\\(x+5)(x-2)=0\\x+5=0\\x_{1}=-5\\x-2=0\\x_{2}=2[/tex]

[tex]2)\frac{8}{x} =3x+2\\8=3x^{2} +2x\\3x^{2} +2x-8=0\\3x^{2} +6x-4x-8=0\\3x(x+2)-4(x+2)=0\\(3x-4)(x+2)=0\\3x-4=0\\3x=4\\x_{1}=\frac{4}{3} \\x+2=0\\x_{2}=-2[/tex]