32. Kaliy gidroksidning 21% li eritmasini tayyorlash uchun 47 gr kaliy oksidini KOH ning necha gramm 7,93% li eritmasida eritish kerak? A) 353 B) 147 C) 284 D) 93.34
More Questions From This User See All
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
A) 353
Объяснение:
K2O + H2O = 2KOH
m(KOH)=((47/94)*2*56)
0.21=(((47/94)*2*56)+(X*0.0793))/(47+X)
X=352.94
From 47 grams of potassium oxide, ((47/94) * 2 * 56) \u003d 56 grams of potassium hydroxide is formed. We take a solution with a content of 7.93 percent for X, compose and solve the mass fraction equation.