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a1exe
@a1exe
August 2022
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3^200=x(mod7)
Нужно найти x
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Denik777
Verified answer
Т.к. 7 - простое число, то по малой теореме Ферма 3^6≡1(mod 7). Поэтому
3^200=3^(6*33+2)=((3^6)^33)*(3^2)≡3^2=9≡2(mod 7).
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Answers & Comments
Verified answer
Т.к. 7 - простое число, то по малой теореме Ферма 3^6≡1(mod 7). Поэтому3^200=3^(6*33+2)=((3^6)^33)*(3^2)≡3^2=9≡2(mod 7).