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17121977
@17121977
July 2022
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решить уравнение
(х-3)кв2 -х(х+4)=15-10х
(х+2)кв2 -5(х-4)=(х-6)(х+6)
х/2-х/3=2
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2014miha
(x^2-6x+9)2-x^2+4x=15-10x
2x^2-12x+18-x^2+4x=15-10x
Приводим подобны слагаемые
x^2+2x+3=0
x1=1
x2=-3
0 votes
Thanks 0
lina9797
Это одно уравнение?)
x/2-x/3=2
(3x-2x)/6=2
x/6=2
x=12
x^2+4x+4-5x+20=
(х-6)(х+6)
x^2-x+24-x^2-26=0
-x-12=0
x=(-12)
0 votes
Thanks 0
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Answers & Comments
2x^2-12x+18-x^2+4x=15-10x
Приводим подобны слагаемые
x^2+2x+3=0
x1=1
x2=-3
x/2-x/3=2
(3x-2x)/6=2
x/6=2
x=12
x^2+4x+4-5x+20=(х-6)(х+6)
x^2-x+24-x^2-26=0
-x-12=0
x=(-12)