Ответ:

8х=16

х=2

10-2у=4

-2у= -6

у=3

(2;3)

[tex]\displaystyle\bf\\+\left \{ {{3x+2y=12} \atop {5x-2y=4}} \right. \\---------\\8x=16\\\\x=16:8=2\\\\2y=12-3x=12-3\cdot 2=12-6=6\\\\y=6:2=3\\\\\\Otvet \ : \ (2 \ ; \ 3)[/tex]