Решение.
Применим свойства корней:
[tex]\bf \sqrt{a\cdot b}=\sqrt{a}\cdot \sqrt{b}\ ,\ \ \boldsymbol{\bf \sqrt[kn]{a^{k\cdot m}}=\sqrt[n]{a^{m}}}[/tex] .
[tex]\bf \sqrt{32}\cdot \sqrt{2}-\sqrt{48}\cdot \sqrt3=\sqrt{2^5}\cdot \sqrt2-\sqrt{2^4\cdot 3}\cdot \sqrt3=\sqrt{2^6}-\sqrt{2^4\cdot 3^2}=\\\\=2^3-2^2\cdot 3=8-4\cdot 3=8-12=-4[/tex]
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Решение.
Применим свойства корней:
[tex]\bf \sqrt{a\cdot b}=\sqrt{a}\cdot \sqrt{b}\ ,\ \ \boldsymbol{\bf \sqrt[kn]{a^{k\cdot m}}=\sqrt[n]{a^{m}}}[/tex] .
[tex]\bf \sqrt{32}\cdot \sqrt{2}-\sqrt{48}\cdot \sqrt3=\sqrt{2^5}\cdot \sqrt2-\sqrt{2^4\cdot 3}\cdot \sqrt3=\sqrt{2^6}-\sqrt{2^4\cdot 3^2}=\\\\=2^3-2^2\cdot 3=8-4\cdot 3=8-12=-4[/tex]