0,3^x^2-14x ⩾ (3 1/3)^24. Created by ToriOfell. algebra-ru

Ответ:х€[2;12]Объяснение:основание степени а =3/10,знак неравенства меняем:метод интервалов:х1=2, х2=12(х-2)×(х-12)<=0+++++ [2] --------- [12] ++++++> хх€[2;12]

3)^24...

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July 2022 1 7 Report

0,3^x^2-14x ⩾ (3 1/3)^24

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kirichekov

Verified answer

Ответ:

х€[2;12]

Объяснение:

${0.3}^{ {x}^{2} - 14x} \geqslant {(3 \frac{1}{3}) }^{24}$

${0.3}^{ {x}^{2} - 14x} = {( \frac{3}{10})}^{ {x}^{2} - 14x}$

${(3 \frac{1}{3})}^{24}={( \frac{10}{3}) }^{24} ={ {(( \frac{3}{10})}^{ - 1}})^{24} =$

${( \frac{3}{10})}^{ {x}^{2} - 14x} \geqslant {( \frac{3}{10})}^{ - 24}$

основание степени а =3/10,

$0 < \frac{3}{10} < 1$

знак неравенства меняем:

${x}^{2} - 14x \leqslant - 24$

${x}^{2} - 14x + 24 \leqslant 0$

метод интервалов:

х1=2, х2=12

(х-2)×(х-12)<=0

+++++ [2] --------- [12] ++++++> х

х€[2;12]

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