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islasha
@islasha
July 2022
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326 найти сумму и произведение корней приведенных квадратных уравнений: 1) х²-х2=0 2) х²-5х-6=0 3) х²+3х +2=0 УМОЛЯЮ ПОМОГИТЕ !!!
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kurosaki1910
1)x^2-6x-7=0
D=b^2-4ac=36+28=64=8^2
x1=6-8/2=-1
x2=6+8/2=7
x1+x2=6; x1*x2=-7
2)x^2-5x-6=0
D=b^2-4ac=25+24=7^2
x1=5-7/2=-1
x2=5+7/2=6
x1+x2=5 ; x1*x2=-6
3)x^2+3x+2=0
D=b^2-4ac=9-8=1
x1=3-1/2=1
x2=3+1/2=2
x1+x2=3 ; x1*x2=2
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islasha
Спасибо ОГРОМНОЕ!
kurosaki1910
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Answers & Comments
D=b^2-4ac=36+28=64=8^2
x1=6-8/2=-1
x2=6+8/2=7
x1+x2=6; x1*x2=-7
2)x^2-5x-6=0
D=b^2-4ac=25+24=7^2
x1=5-7/2=-1
x2=5+7/2=6
x1+x2=5 ; x1*x2=-6
3)x^2+3x+2=0
D=b^2-4ac=9-8=1
x1=3-1/2=1
x2=3+1/2=2
x1+x2=3 ; x1*x2=2