[tex]\displaystyle 2\frac{3}{4}-4(2\frac{1}{6}x-5\frac{5}{8})-\frac{1}{3}x=7\frac{1}{4}\\ \\\frac{11}{4}-4(\frac{13}{6}x-\frac{45}{8})-\frac{1}{3}x=\frac{29}{4}\\ \\\frac{11}{4}-\frac{26}{3}x+\frac{45}{2}-\frac{1}{3}x=\frac{29}{4}\\ \\\frac{101}{4}-\frac{26}{3}x-\frac{1}{3}x=\frac{29}{4}\\ \\303-104x-4x=87\\ 303-108x=87\\ -108x=87-303\\ -108x=-126\\ x=2[/tex]