Home
О нас
Products
Services
Регистрация
Войти
Поиск
Svitlanasem10
@Svitlanasem10
August 2021
1
8
Report
3^(2х+1)+8•3^х -3≥0
Помогите, очень надо
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
kolesnik80
Verified answer
3*3^(2x)+8*3^x-3≥0. Положим 3^x=t, t>0, тогда
3t²+8t-3≥0, 3(t+3)(t-1/3)≥0.
Поскольку t>0, то t+3>3, отсюда t-1/3≥0, т.е.3^x≥1/3, 3^x≥3^(-1),x≥-1, х∈[-1;+∞)
0 votes
Thanks 0
More Questions From This User
See All
Svitlanasem10
August 2021 | 0 Ответы
znajdit mnozhinu rozvyazkiv nerivnosti 013h0012 h
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "3^(2х+1)+8•3^х -3≥0 Помогите, очень надо..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
3*3^(2x)+8*3^x-3≥0. Положим 3^x=t, t>0, тогда3t²+8t-3≥0, 3(t+3)(t-1/3)≥0.
Поскольку t>0, то t+3>3, отсюда t-1/3≥0, т.е.3^x≥1/3, 3^x≥3^(-1),x≥-1, х∈[-1;+∞)