3√2sin(-1125°)помогите пожалуйста. Created by matfejbuharev6. algebra-ru

3√2sin(-1125°)помогите пожалуйста...

matfejbuharev6 @matfejbuharev6

July 2022 1 8 Report

3√2sin(-1125°)

помогите пожалуйста

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NNNLLL54

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Ответ:

$3\sqrt2\, sin(-1125^\circ )=3\sqrt2\, sin(-3\cdot 360^\circ -45^\circ )=3\sqrt2\, sin(-45^\circ )=\\\\=-3\sqrt2\, sin45^\circ =-3\sqrt2\cdot \dfrac{\sqrt2}{2}=-3$

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