Решите прошу!!! а) (1/6+2/3)*3 , б) (17/30-2/15) :13 , в) (1/8+3/4) :5 , г) (4/3+1/9)*4 , д) (1/2+1/3)*2 , е) (1/2-1/3)*3. Created by zyflb. matematika-ru

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August 2022 1 6 Report

Решите прошу!!! а) (1/6+2/3)*3 , б) (17/30-2/15) :13 , в) (1/8+3/4) :5 , г) (4/3+1/9)*4 , д) (1/2+1/3)*2 , е) (1/2-1/3)*3

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VasiaZozulia А) (1/6+2/3)*3
(1 + 2*2)/6 * 3 = 5/6 * 3 = 5/2 = 2 1/2
б) (17/30-2/15) :13
(17 - 2 * 2)/30 * 1/13 = 13/30 * 1/13 = 1/30
в) (1/8+3/4) :5
(1 + 2*3)/8 * 1/5 = 7/8 * 1/5 = 7/40
г) (4/3+1/9)*4
(4*3 + 1)/9 * 4 = 13/9 * 4 = 52/9 = 5 7/9
д) (1/2+1/3)*2
(1*3 + 1*2)/6 * 2 = 5/6 * 2 = 5/3 = 1 2/3
е) (1/2-1/3)*3
(1*3 - 1*2)/6 * 3 = 1/6 * 3 = 1/2

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