Ответ:

[tex] \frac{x + 3}{4} - \frac{y - 4}{8} = 1 \frac{3}{4} \\ \frac{x - 4}{6} + \frac{y + 2}{9} = - \frac{1}{2} \\ \\ \frac{2x + 6 - y + 4}{8} = \frac{14}{8} \\ \frac{3x - 12 + 2y + 4}{18} = - \frac{9}{18} \\ \\ 2x - y + 10 = 14 \\ 3x + 2y - 8 = - 9 \\ \\ y = 2x - 4 \\ 3x + 2(2x - 4) = - 1 \\ \\ y = 2x - 4 \\ 3x + 4x - 8 = - 1 \\ \\ y = 2x - 4 \\ 7x = 7 \\ \\ y = 2 - 4\\ x = 1 \\ \\ y = - 2 \\ x = 1[/tex]