Раскройте скобки в произведении:
а) 1/4(4х - 16)
б) -1/3(3х+12)
в) (2х-3у)*(-3)
г) 2m(m-n)
д) 2x(a+3b-c)
е) -c(x-2y+3z)
Или кто учится по учебнику Алгебра 7 класс Дорофеев №294 параграф 3.3
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а)![\frac{1}{4}(4x-16)=\frac{1}{4}\cdot4x-\frac{1}{4}\cdot16=\frac{4x}{4}-\frac{16}{4}=x-4 \frac{1}{4}(4x-16)=\frac{1}{4}\cdot4x-\frac{1}{4}\cdot16=\frac{4x}{4}-\frac{16}{4}=x-4](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%284x-16%29%3D%5Cfrac%7B1%7D%7B4%7D%5Ccdot4x-%5Cfrac%7B1%7D%7B4%7D%5Ccdot16%3D%5Cfrac%7B4x%7D%7B4%7D-%5Cfrac%7B16%7D%7B4%7D%3Dx-4)
б)![-\frac{1}{3}(3x+12)=-\frac{1}{3}\cdot3x+(-\frac{1}{3}\cdot12)=-\frac{3x}{3}-\frac{12}{3}=-x-4 -\frac{1}{3}(3x+12)=-\frac{1}{3}\cdot3x+(-\frac{1}{3}\cdot12)=-\frac{3x}{3}-\frac{12}{3}=-x-4](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B3%7D%283x%2B12%29%3D-%5Cfrac%7B1%7D%7B3%7D%5Ccdot3x%2B%28-%5Cfrac%7B1%7D%7B3%7D%5Ccdot12%29%3D-%5Cfrac%7B3x%7D%7B3%7D-%5Cfrac%7B12%7D%7B3%7D%3D-x-4)
в) (2х-3у)·(-3)=-3(2х-3у)=-3·2x-3·(-3y)=-6x+9y
г) 2m(m-n)=2m·m-2m·n=2m²-2mn
д) 2x(a+3b-c)=2x·a+2x·3b-2x·c=2ax+6bx-2cx
е) -c(x-2y+3z)=-c·x-c·(-2y)-c·3z=-cx+2cy-3cz