х-6/2-3=х/3
x-3-3=x/3
x-6=x/3
3x-18=x
3x-x=18
2x=18
x=9
|3(x-5)+1|=2
|3x-15+1|=2
|3x-14|=2
3x-14=±2
[tex]x_{1}[/tex] = 16/3
[tex]x_{2}[/tex] = 4
[tex]\displaystyle\bf\\1)\\\\\frac{x-6}{2} -3=\frac{x}{3}\\\\\\\frac{x-6}{2}\cdot 6-3\cdot 6=\frac{x}{3}\cdot 6\\\\\\(x-6)\cdot 3-18=2x\\\\3x-18-18=2x\\\\3x-2x=36\\\\x=36\\\\\\2)\\\\\Big|3(x-5)+1\Big|=2\\\\\\\left[\begin{array}{ccc}3(x-5)+1=-2\\3(x-5)+1=2\end{array}\right\\\\\\\left[\begin{array}{ccc}3x-15+1=-2\\3x-15+1=2\end{array}\right\\\\\\\left[\begin{array}{ccc}3x=12\\3x=16\end{array}\right\\\\\\\left[\begin{array}{ccc}x=4\\x=5\dfrac{1}{3} \end{array}\right[/tex]
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Answers & Comments
х-6/2-3=х/3
x-3-3=x/3
x-6=x/3
3x-18=x
3x-x=18
2x=18
x=9
|3(x-5)+1|=2
|3x-15+1|=2
|3x-14|=2
3x-14=±2
[tex]x_{1}[/tex] = 16/3
[tex]x_{2}[/tex] = 4
[tex]\displaystyle\bf\\1)\\\\\frac{x-6}{2} -3=\frac{x}{3}\\\\\\\frac{x-6}{2}\cdot 6-3\cdot 6=\frac{x}{3}\cdot 6\\\\\\(x-6)\cdot 3-18=2x\\\\3x-18-18=2x\\\\3x-2x=36\\\\x=36\\\\\\2)\\\\\Big|3(x-5)+1\Big|=2\\\\\\\left[\begin{array}{ccc}3(x-5)+1=-2\\3(x-5)+1=2\end{array}\right\\\\\\\left[\begin{array}{ccc}3x-15+1=-2\\3x-15+1=2\end{array}\right\\\\\\\left[\begin{array}{ccc}3x=12\\3x=16\end{array}\right\\\\\\\left[\begin{array}{ccc}x=4\\x=5\dfrac{1}{3} \end{array}\right[/tex]