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волккккк
@волккккк
July 2022
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3,4+2y=7 (y-2,3), 4 (5x+2)=10 (2x-3)÷15 решите
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kaliningrad2017
3,4+2y=7(y-2,3)
3,4+2y=7y-16,1
2y-7y=-16,1-3,4
-5y=-19,5
y=-3,9
4(5x+2)=10
20x+8=10
20x=12
x=0,6
(2x-3):152x-3_15*_ дробь
1 votes
Thanks 0
jekadva
y = 3,9
jekadva
неверно 4(5x+2)=10
20x+8=10
20x=12
x=0,6
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Answers & Comments
3,4+2y=7y-16,1
2y-7y=-16,1-3,4
-5y=-19,5
y=-3,9
4(5x+2)=10
20x+8=10
20x=12
x=0,6
(2x-3):152x-3_15*_ дробь
20x+8=10
20x=12
x=0,6