K2SO4+BaCl2=BaSO4+2KCl
nK2SO4=34.8/174=0.2моль
nBaCl2=62.4/208=0.3моль (0.1 избыток)
mBaSO4=0.2×233=46.6г
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K2SO4+BaCl2=BaSO4+2KCl
nK2SO4=34.8/174=0.2моль
nBaCl2=62.4/208=0.3моль (0.1 избыток)
mBaSO4=0.2×233=46.6г