х-у=√2⇒х>y
1/3√6=1/√54=√1/54
4√1/32=√16*1/32=√1/2
0,5=√0,25=√1/4
1/3=√1/9
1/3√6; 1/3; 0,5; 4√1/32;
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
х-у=√2⇒х>y
1/3√6=1/√54=√1/54
4√1/32=√16*1/32=√1/2
0,5=√0,25=√1/4
1/3=√1/9
1/3√6; 1/3; 0,5; 4√1/32;