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070888
@070888
September 2021
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3(5-4a)-(12a-7) при a 0.5
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Кsеnia
=(15-12*0.5)-(12*0.5-7)=90-(-1)=91
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Jarik78
3(5-4*0,5)-(12*0,5-7)= 3(5-2)-(6-7)=9+1=10
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Answers & Comments
3(5-4*0,5)-(12*0,5-7)= 3(5-2)-(6-7)=9+1=10