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Илюзик2003
@Илюзик2003
November 2021
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найдите натуральное число, удовлетворяющее неравенству 4 целых 1/6 < Х + 1 целая 1/3 < пять целых 1/3
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DedushkaBake
От каждой части неравенства отнимем 1 1/3
4 1/6-1 1/3 <x<5 1/3-1 1/3
25/6-4/3 <x<4
25/6-8/6<x<4
17/6<x<4
2 5/6 <x<4
x=3
11 votes
Thanks 20
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4 1/6-1 1/3 <x<5 1/3-1 1/3
25/6-4/3 <x<4
25/6-8/6<x<4
17/6<x<4
2 5/6 <x<4
x=3