36. Найти сумму корней (в градусах) уравнения 4cos2 2x +2(√3+1)cos2x+√3=0, принадлежащих отрезку [0; п]. TOUL LIM

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sqkuwy cos(2x) + sin(2x) = cos(x)

2cos(x) + 2sin(x)cos(x) = cos(x)

cos(x) = 0 --> π/2 + πk

2cos(x) + 2sin(x) = 1

sin(x) + cos(x) = 1/2

√2sin(x + π/4) = 1/2

sin(x + π/4) = 1/2√2

x = 3π/4 - arcsin(1/2√2) +2πk

x = -π/4 + arcsin(1/2√2) +2πk

k - целое.

Корень, принадлежащий заданному интервалу: x= 0

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