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[tex]9 \frac{1}{3} \div (9x - 2 \frac{1}{3} ) = 6 \\ 9x - 2 \frac{1}{3} = 9 \frac{1}{3} \div 6 \\ 9x - 2 \frac{1}{3} = \frac{28}{3 \times 6} \\ 9x - 2 \frac{1}{3} = \frac{14}{9} \\ 9x = 1 \frac{5}{9} + 2 \frac{1}{3} \\ 9x = 1 \frac{5}{9} + 2 \frac{3}{9} \\9 x = 3 \frac{8}{9} \\ x = 3 \frac{8}{9} \div 9 \\ x = \frac{35}{9 \times 9} \\ x = \frac{35}{81} [/tex]