дана функция y=f(x),где f(x)= -3x+2. Найдите:а) f(0),f(-3),f(2/3),f(-1/3)
f(0)=-3*0+2=2
f(2/3)=-3*(2/3)+2=0
f(-1/3)=-3*(-1/3)+2=3
f(-3)=-3*(-3)+2=9+2=11
f(2/3)=-3*2/3+2=0
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f(0)=-3*0+2=2
f(2/3)=-3*(2/3)+2=0
f(-1/3)=-3*(-1/3)+2=3
f(0)=-3*0+2=2
f(-3)=-3*(-3)+2=9+2=11
f(2/3)=-3*2/3+2=0
f(-1/3)=-3*(-1/3)+2=3